perf: avoid unnecessary string copy during regex parsing#144
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Optimized RegexParser.removeWhitespaces to perform an early return if no whitespace is found in the input string. This avoids unnecessary StringBuilder allocation and string copying for the vast majority of regular expressions that do not contain whitespace. Co-authored-by: google-labs-jules[bot] <161369871+google-labs-jules[bot]@users.noreply.github.com>
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Optimized RegexParser.removeWhitespaces to perform an early return if no whitespace is found in the input string. This avoids unnecessary StringBuilder allocation and string copying for the vast majority of regular expressions that do not contain whitespace. Co-authored-by: google-labs-jules[bot] <161369871+google-labs-jules[bot]@users.noreply.github.com>
Optimized RegexParser.removeWhitespaces to perform an early return if no whitespace is found in the input string. This avoids unnecessary StringBuilder allocation and string copying for the vast majority of regular expressions that do not contain whitespace. Co-authored-by: google-labs-jules[bot] <161369871+google-labs-jules[bot]@users.noreply.github.com>
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What:
Added a fast-path optimization in
RegexParser.removeWhitespacesthat checks for whitespace before attempting to build a new string.Why:
Most regular expressions processed by this library do not contain whitespace. Previously, every regex was unnecessarily copied character-by-character into a
StringBuilder, resulting in pointless object allocations and garbage collection overhead.Impact:
In a benchmark with a 5-million iteration loop processing
(a|b)*abb(a|b)*abb(a|b)*abb, the execution time forremoveWhitespacesdropped from ~1247ms down to ~591ms, a ~52% performance improvement.Measurement:
The improvement can be measured using any Java profiler tracking memory allocations or with a simple micro-benchmark timing the
RegexParser.parsemethod on whitespace-free expressions.PR created automatically by Jules for task 6510452002481169711 started by @Tugamer89