Using the type statement to create a new int type, expr is unable to compare the new type with int.

[zhengycxxxx]

NewIntType==1 will be false, How to make it true.

import (
	"fmt"
	"testing"

	"github.com/antonmedv/expr"
)

type newIntType int

const (
	newIntTypeA newIntType = 1
	newIntTypeB newIntType = 2
)

func TestCalBool1(t *testing.T) {
	type XX struct {
		NewIntType newIntType
	}
	val := &XX{
		NewIntType: newIntTypeA,
	}
	s := "NewIntType==1"
	fmt.Println(CalBool(s, val))
}

func CalBool(input string, env interface{}) (bool, error) {
	output, err := cal(input, env)
	if err != nil {
		return false, err
	}

	if val, ok := output.(bool); ok {
		return val, nil
	}

	return false, err
}

func cal(input string, env interface{}) (interface{}, error) {
	return expr.Eval(input, env)
}