-
Notifications
You must be signed in to change notification settings - Fork 1
Expand file tree
/
Copy path205_Isomorphic_Strings.cpp
More file actions
43 lines (38 loc) · 1.66 KB
/
Copy path205_Isomorphic_Strings.cpp
File metadata and controls
43 lines (38 loc) · 1.66 KB
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
/*
205. Isomorphic Strings
Given two strings s and t, determine if they are isomorphic.
Two strings s and t are isomorphic if the characters in s can be replaced to get t.
All occurrences of a character must be replaced with another character while preserving the order of characters. No two characters may map to the same character, but a character may map to itself.
Example 1:
Input: s = "egg", t = "add"
Output: true
Example 2:
Input: s = "foo", t = "bar"
Output: false
Example 3:
Input: s = "paper", t = "title"
Output: true
Constraints:
1 <= s.length <= 5 * 104
t.length == s.length
s and t consist of any valid ascii character
*/
class Solution {
public:
bool isIsomorphic(string s, string t) {
vector<int> indexS(200, 0); // Stores index of characters in string s
vector<int> indexT(200, 0); // Stores index of characters in string t
int len = s.length(); // Get the length of both strings
if(len != t.length()) { // If the lengths of the two strings are different, they can't be isomorphic
return false;
}
for(int i = 0; i < len; i++) { // Iterate through each character of the strings
if(indexS[s[i]] != indexT[t[i]]) { // Check if the index of the current character in string s is different from the index of the corresponding character in string t
return false; // If different, strings are not isomorphic
}
indexS[s[i]] = i + 1; // updating position of current character
indexT[t[i]] = i + 1;
}
return true; // If the loop completes without returning false, strings are isomorphic
}
};